Which notation documents a woman with four pregnancies, three term births, one miscarriage at nine weeks, and three living children?

• A. G4P3014
• B. G4P3003
• C. G4P3013
• D. G4P3024

Answer: (C)

The notation tests how obstetric history is recorded using parity cues. Gravida is the total number of pregnancies a woman has had. Parity (Para) breaks down the outcomes of those pregnancies into four numbers in the order: term births, preterm births, abortions (miscarriages or induced abortions), and living children.

In this scenario, the woman has had four pregnancies (G4). She has three term births, no preterm births, one abortion (a miscarriage at nine weeks), and three living children. Put together, that matches the string 3 (term), 0 (preterm), 1 (abortion), 3 (living) after G4, which is written as G4P3013. In modern shorthand, this corresponds to G4T3P0A1L3 as well.